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Easy

Question

AB is a chord of the parabola y2 = 4ax with vertex at A. BC is drawn perpendicular to AB meeting the axis at C. The projection of BC on the x-axis is-

  1. a    
  2. 2a    
  3. 4a    
  4. 8a    

The correct answer is: 4a


    Let B be (at2, 2at)

    Slope of AB =fraction numerator 2 over denominator t end fraction.
    Equation of BC is y – 2at = – fraction numerator t over denominator 2 end fraction (x – at2).
    This meets y = 0 at C whose x-coordinate = 4a + at2
    D = (at2, 0)
    thereforeDC = 4a + at2 – at2 = 4a.

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