Maths-
General
Easy

Question

Assertion (A) : Graph of open curly brackets left parenthesis x comma y right parenthesis divided by y equals 2 to the power of negative x end exponent text  and  end text x comma y element of R close curly brackets
Reason (R) : In the expression am/n, where a, m, n × J+, m represents the power to which a is be raised, whereas n determines the root to be taken; these two processes may be administered in either order with the same result.

  1. If both (A) and (R) are true, and (R) is the correct explanation of (A) .    
  2. If both (A) and (R) are true but (R) is not the correct explanation of (A) .    
  3. If (A) is true but (R) is false.    
  4. If (A) is false but (R) is true.    

The correct answer is: If (A) is false but (R) is true.

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Assertion: The period of f left parenthesis x right parenthesis equals s i n invisible function application 2 x c o s invisible function application left square bracket 2 x right square bracket minus c o s invisible function application 2 x s i n invisible function application left square bracket 2 x right square bracket is 1/2.
Reason: The period of x – [x] is 1.

Assertion: The period of f left parenthesis x right parenthesis equals s i n invisible function application 2 x c o s invisible function application left square bracket 2 x right square bracket minus c o s invisible function application 2 x s i n invisible function application left square bracket 2 x right square bracket is 1/2.
Reason: The period of x – [x] is 1.

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Assertion : Fundamental period of c o s invisible function application x plus c o t invisible function application x text  is  end text 2 pi.
Reason : If the period of f(x) is T subscript 1 end subscript and the period of g(x) is T subscript 2 end subscript, then the fundamental period of f(x) + g(x) is the L.C.M. of T subscript 1 end subscript and T

Assertion : Fundamental period of c o s invisible function application x plus c o t invisible function application x text  is  end text 2 pi.
Reason : If the period of f(x) is T subscript 1 end subscript and the period of g(x) is T subscript 2 end subscript, then the fundamental period of f(x) + g(x) is the L.C.M. of T subscript 1 end subscript and T

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Assertion: The function defined by f left parenthesis x right parenthesis equals x to the power of 3 end exponent plus a x to the power of 2 end exponent plus b x plus c is invertible if and only if a to the power of 2 end exponent less or equal than 3 b.
Reason: A function is invertible if and only if it is one-to-one and onto function.

Assertion: The function defined by f left parenthesis x right parenthesis equals x to the power of 3 end exponent plus a x to the power of 2 end exponent plus b x plus c is invertible if and only if a to the power of 2 end exponent less or equal than 3 b.
Reason: A function is invertible if and only if it is one-to-one and onto function.

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Assertion : f left parenthesis x right parenthesis equals s g n left parenthesis x minus vertical line x vertical line right parenthesiscan never become positive.
Reason : f(x) = sgn x is always a positive function.

Assertion : f left parenthesis x right parenthesis equals s g n left parenthesis x minus vertical line x vertical line right parenthesiscan never become positive.
Reason : f(x) = sgn x is always a positive function.

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If f (x) = open curly brackets table row cell e to the power of cos invisible function application x end exponent end cell cell sin invisible function application x text for  end text vertical line x vertical line less or equal than 2 end cell row cell text 2, end text end cell cell text otherwise end text end cell end table comma text then  end text not stretchy integral subscript text -2 end text end subscript superscript 3 end superscript f ​ left parenthesis x right parenthesis d x equals close

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The value of the integral not stretchy integral subscript e to the power of negative 1 end exponent end subscript superscript e to the power of 2 end exponent end superscript open vertical bar fraction numerator log subscript e end subscript invisible function application blank x over denominator x end fraction close vertical bar dx is :

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Assertion : Let f colon R minus left curly bracket 1 , 2 comma 3 right curly bracket rightwards arrow R be a function defined by f(x) = fraction numerator 1 over denominator x minus 1 end fraction plus fraction numerator 2 over denominator x minus 2 end fraction plus fraction numerator 3 over denominator x minus 3 end fraction. Then f is many-one function.
Reason : If either f apostrophe left parenthesis x right parenthesis greater than 0 or f to the power of apostrophe left parenthesis x right parenthesis less than 0 comma for all x element ofdomain of f, then y = f(x) is one-one function.</span

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Assertion : Fundamental period of c o s invisible function application x plus c o t invisible function application x text  is  end text 2 pi.
Reason : If the period of f(x) is T subscript 1 end subscript and the period of g(x) is T subscript 2 end subscript, then the fundamental period of f(x) + g(x) is the L.C.M. of T subscript 1 end subscript and T

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Reason : If the period of f(x) is T subscript 1 end subscript and the period of g(x) is T subscript 2 end subscript, then the fundamental period of f(x) + g(x) is the L.C.M. of T subscript 1 end subscript and T

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