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Maths-

General

Easy

Question

If f : R → R is continuous and differentiable function such that $not stretchy integral subscript negative 1 end subscript superscript x end superscript blank$ f(t) dt + f¢¢¢ (3) $not stretchy integral subscript x end subscript superscript 0 end superscript d t equals not stretchy integral subscript 1 end subscript superscript x end superscript blank$ t³
dt – f ¢ (1) $not stretchy integral subscript 0 end subscript superscript x end superscript blank$ t² dt + f ¢¢ (2) $not stretchy integral subscript x end subscript superscript 3 end superscript blank$ t. dt, then the value of f ¢ (4) is :

48 – 8 f ¢ (1) + f ¢¢ (2)
48 – 8 f ¢ (1) – f ¢¢ (2)
48 + 8 f ¢ (1) + f ¢¢ (2)
None of these.

The correct answer is: 48 – 8 f ¢ (1) – f ¢¢ (2)

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