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Maths-

General

Easy

Question

If two chords, each bisected by the x - axis can be drawn to the circle, $2 open parentheses x to the power of 2 end exponent plus y to the power of 2 end exponent close parentheses minus 2 a x minus b y equals 0 left parenthesis a not equal to 0 comma b not equal to 0 right parenthesis text end text$ from the point $text end text left parenthesis a comma b divided by 2 right parenthesis text end text$ then :

$a^{2} > 8 b^{2}$
$b^{2} > 2 a^{2}$
$a^{2} > 2 b^{2}$
$a^{2} = 2 b^{2}$

The correct answer is: $a to the power of 2 end exponent greater than 2 b to the power of 2 end exponent$

Related Questions to study

The radius of the least circle passing through the point (8, 4) and cutting the circle $x to the power of 2 end exponent plus y to the power of 2 end exponent equals 40$ orthogonally is

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