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Maths-

General

Easy

Question

In the figure, if $angle 3 colon angle 6 equals 2 colon 7 text then end text angle 2 colon angle 7 equals$

2 : 7
7 : 2
1 : 2
2 : 1

hint Hint:

Corresponding angles are equal
Sum of consecutive angles are 180 that is they are supplementary

The correct answer is: 7 : 2

Step 1
$angle 3 colon angle 6 space space equals 2 colon 7 angle 3 plus angle 6 space equals space 180 space left parenthesis s u p p l e m e n t a r y space a n g l e s right parenthesis L e t space angle 3 space b e space 2 x space a n d space angle 6 space b e space 7 x 2 x plus 7 x space equals 180 x equals space 180 divided by 9 x equals 20 angle 3 space equals space 40 space a n d space angle 6 space equals space 140$
Step 2
Now $angle 2 space equals angle 6 space space equals space 140 to the power of ring operator space left parenthesis C o r r e s p o n d i n g space a n g l e s space a r e space e q u a l right parenthesis angle 3 space equals space angle 7 space space space equals space 40 to the power of ring operator space space end exponent space left parenthesis C o r r e s p o n d i n g space a n g l e s space a r e space e q u a l right parenthesis angle 2 colon angle 7 space equals 140 colon 40 angle 2 colon angle 7 space equals 7 colon 2 space$ ,

Related Questions to study

In the figure, n is transversal to lines $l comma m text and end text l parallel to m text . end text$ $text If end text angle 3 equals 70 to the power of ring operator end exponent text then end text angle 8 equals ?$

angle on a straight line is always 180⁰

In the figure, n is transversal to lines $l comma m text and end text l parallel to m text . end text$ $text If end text angle 3 equals 70 to the power of ring operator end exponent text then end text angle 8 equals ?$

angle on a straight line is always 180⁰

In the figure, n is transversal to $l comma m$ then $left parenthesis x plus y plus z right parenthesis minus left parenthesis p plus q plus r right parenthesis equals ?$

In the figure, n is transversal to $l comma m$ then $left parenthesis x plus y plus z right parenthesis minus left parenthesis p plus q plus r right parenthesis equals ?$

According to the data given in figure, x = ?

Angle in complete circle is 360^₀

According to the data given in figure, x = ?

Angle in complete circle is 360^₀

parallel

If ABCD is a square as shown in the figure then which of the following are adjacent sides ?

if two vertices in a graph/diagram are connected by an edge then they are adjacent vertices

If ABCD is a square as shown in the figure then which of the following are adjacent sides ?

if two vertices in a graph/diagram are connected by an edge then they are adjacent vertices

In the following figure, a pair of adjacent vertices is

if two vertices in a graph/diagram are connected by an edge then are adjacent vertices

In the following figure, a pair of adjacent vertices is

if two vertices in a graph/diagram are connected by an edge then are adjacent vertices

Find the value of x from the following Venn diagram if

Find the value of x from the following Venn diagram if

parallel

In Venn diagram, $left parenthesis A intersection C right parenthesis union left parenthesis B intersection C right parenthesis equals$

intersection of superset with subset is subset

In Venn diagram, $left parenthesis A intersection C right parenthesis union left parenthesis B intersection C right parenthesis equals$

intersection of superset with subset is subset

S₁ : Generally square planar complexes show geometrical isomerism but do not exhibit optical isomerism because they do not possess planer of symmetry.
S₂ : $capital delta subscript t end subscript equals fraction numerator 4 over denominator 9 end fraction capital delta subscript 0 end subscript$
S₃ : In octahedral complexes each electron entering the t_2g orbitals stabilizes the complex ion by 0.4 $capital delta subscript 0 end subscript$ and each electron entering the e.gorbital destabilizes the complex by an amount of 0.6 Δ₀.

S₁ : Generally square planar complexes show geometrical isomerism but do not exhibit optical isomerism because they do not possess planer of symmetry.
S₂ : $capital delta subscript t end subscript equals fraction numerator 4 over denominator 9 end fraction capital delta subscript 0 end subscript$
S₃ : In octahedral complexes each electron entering the t_2g orbitals stabilizes the complex ion by 0.4 $capital delta subscript 0 end subscript$ and each electron entering the e.gorbital destabilizes the complex by an amount of 0.6 Δ₀.

chemistry-General

All the following complex show decreases in their weights when placed in a magnetic balance then the group of complexes having tetrahedral geometry is :
i) Ni(CO)₄
ii) K[AgF₄ ]
iii) Na₂ [Zn(CN)₄ ]
iv) K₂ [PtCl₄ ]
v) [RhCl(PPh₃)₃ ]

All the following complex show decreases in their weights when placed in a magnetic balance then the group of complexes having tetrahedral geometry is :
i) Ni(CO)₄
ii) K[AgF₄ ]
iii) Na₂ [Zn(CN)₄ ]
iv) K₂ [PtCl₄ ]
v) [RhCl(PPh₃)₃ ]

chemistry-General

parallel

$N i C l subscript 2 end subscript stack stack ⟶ with K C N on top with H C N below$ complex A
$N i C l subscript 2 end subscript stack stack ⟶ with K C l on top with text excess end text below$ complex B
A & B complexes have the co-ordination number 4.
The IUPAC name of complexes ‘A’ & ‘B’ are respectively :

$N i C l subscript 2 end subscript stack stack ⟶ with K C N on top with H C N below$ complex A
$N i C l subscript 2 end subscript stack stack ⟶ with K C l on top with text excess end text below$ complex B
A & B complexes have the co-ordination number 4.
The IUPAC name of complexes ‘A’ & ‘B’ are respectively :

chemistry-General

On treatment of 100 mL 0.1 M Solution of CoCl3.6H2Owith excess AgNO₃, $1.2 cross times 1022$ ions are precipitated The complex is :

On treatment of 100 mL 0.1 M Solution of CoCl3.6H2Owith excess AgNO₃, $1.2 cross times 1022$ ions are precipitated The complex is :

chemistry-General

How many EDTA (ethylenediaminetetraacetic acid) molecules are required to make an octahedral complex with a Ca2+ ion ?

How many EDTA (ethylenediaminetetraacetic acid) molecules are required to make an octahedral complex with a Ca2+ ion ?

chemistry-General

parallel

In Fe(CO)₅, the Fe – C bond possesses :

In Fe(CO)₅, the Fe – C bond possesses :

chemistry-General

When degenerate d-orbitals of an iSol. ated atom/ion come under influence of magnetic field of ligands, the degeneracy is lost The two set $t subscript 2 g end subscript open parentheses d subscript x y end subscript comma d subscript y z end subscript comma d subscript x z end subscript close parentheses$ and $open parentheses d subscript z to the power of 2 end exponent end subscript comma d subscript x to the power of 2 end exponent minus y to the power of 2 end exponent end subscript close parentheses$ are either stabilized or destrabilized depending upon the nature of magnetic fieldIt can be expressed diagrammatically as:
Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally, for $capital delta$ is about 4/9 times to $capital delta subscript 0 end subscript$ tetrahedral complexes, (CFSE for octahedral complex)This energy lies in visible region and i.e., why electronic transition are responsible for colour Such transitions are not possible with d0 and d10 configuration.
Crystal field stabilization energy for [ $open square brackets C o F subscript 6 end subscript close square brackets to the power of 3 minus end exponent$ in terms of parameter Dq is – $left parenthesis capital delta equals 10 D q right parenthesis$

When degenerate d-orbitals of an iSol. ated atom/ion come under influence of magnetic field of ligands, the degeneracy is lost The two set $t subscript 2 g end subscript open parentheses d subscript x y end subscript comma d subscript y z end subscript comma d subscript x z end subscript close parentheses$ and $open parentheses d subscript z to the power of 2 end exponent end subscript comma d subscript x to the power of 2 end exponent minus y to the power of 2 end exponent end subscript close parentheses$ are either stabilized or destrabilized depending upon the nature of magnetic fieldIt can be expressed diagrammatically as:
Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally, for $capital delta$ is about 4/9 times to $capital delta subscript 0 end subscript$ tetrahedral complexes, (CFSE for octahedral complex)This energy lies in visible region and i.e., why electronic transition are responsible for colour Such transitions are not possible with d0 and d10 configuration.
Crystal field stabilization energy for [ $open square brackets C o F subscript 6 end subscript close square brackets to the power of 3 minus end exponent$ in terms of parameter Dq is – $left parenthesis capital delta equals 10 D q right parenthesis$

chemistry-General

When degenerate d-orbitals of an iSolated atom/ion come under influence of magnetic field of ligands, the degeneracy is lost The two set $t subscript 2 g end subscript open parentheses d subscript x y end subscript comma d subscript y z end subscript comma d subscript x z end subscript close parentheses$ and $open parentheses d subscript z to the power of 2 end exponent end subscript comma d subscript x to the power of 2 end exponent minus y to the power of 2 end exponent end subscript close parentheses$ are either stabilized or destrabilized depending upon the nature of magnetic fieldIt can be expressed diagrammatically as:
Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally, for $capital delta$ is about 4/9 times to $capital delta subscript 0 end subscript$ tetrahedral complexes, (CFSE for octahedral complex)This energy lies in visible region and i.e., why electronic transition are responsible for colour Such transitions are not possible with d0 and d10 configuration.
$T i subscript left parenthesis a q right parenthesis end subscript superscript 3 plus end superscript$ is purple while $T i subscript left parenthesis a q right parenthesis end subscript superscript 3 plus end superscript$ is colourless because –

When degenerate d-orbitals of an iSolated atom/ion come under influence of magnetic field of ligands, the degeneracy is lost The two set $t subscript 2 g end subscript open parentheses d subscript x y end subscript comma d subscript y z end subscript comma d subscript x z end subscript close parentheses$ and $open parentheses d subscript z to the power of 2 end exponent end subscript comma d subscript x to the power of 2 end exponent minus y to the power of 2 end exponent end subscript close parentheses$ are either stabilized or destrabilized depending upon the nature of magnetic fieldIt can be expressed diagrammatically as:
Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally, for $capital delta$ is about 4/9 times to $capital delta subscript 0 end subscript$ tetrahedral complexes, (CFSE for octahedral complex)This energy lies in visible region and i.e., why electronic transition are responsible for colour Such transitions are not possible with d0 and d10 configuration.
$T i subscript left parenthesis a q right parenthesis end subscript superscript 3 plus end superscript$ is purple while $T i subscript left parenthesis a q right parenthesis end subscript superscript 3 plus end superscript$ is colourless because –

chemistry-General

parallel

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