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Maths-

General

Easy

Question

In the given figure, area (parallelogram ABCD) = 48 $c m to the power of 2 end exponent$ and $F C parallel to A B$ Find area of $text IIgm end text text ABEF end text$

12 ${c m}^{2}$
24 ${c m}^{2}$
18 ${c m}^{2}$
8 ${c m}^{2}$

The correct answer is: 24 $c m to the power of 2 end exponent$

we should find the area of the given parallelogram
$\Rightarrow$ In given figure, we can see that parallelogram $A B C D$ and parallelogram $A B E F$ both are lies between same parallel line that is $F C$ and $A B$ .
$\Rightarrow$ And parallelogram $A B C D$ and $A B E F$ contains same base that is $A B$ .
$\Rightarrow$ So, we know that parallelogram on same base and between same parallels are equal in area.
$\Rightarrow$ So, $A r e a (A B C D) = A r e a (A B E F)$ ------ ( 1 )
$\Rightarrow$ We have given $A r e a (A B C D) = 48 c m 2$
From $(1)$ we get,
Area of parallelogram $A B E F = 48 c m 2$

Hence option C is correct

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parallel

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