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Maths-

General

Easy

Question

In the given figure $C E perpendicular A B comma m angle A C E equals 20 to the power of ring operator end exponent text end text$ and $text end text m angle A B D equals 50 to the power of ring operator end exponent$ Then m $angle$ BDA is

60°
45°
75°
90°

hint Hint:

In a triangle, all angles sum up to 180°
In triangle AEC, 90°+20°+ $angle$ EAC = 180°
$angle$ EAC = 70°
In triangle ADB, 50°+70°+ $angle$ BDA = 180°
$angle$ BDA =60°

The correct answer is: 60°

To find $angle$ BDA in a given figure.

Therefore, using triangle property, $angle$ BDA =60°.

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