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Maths-

General

Easy

Question

In the given figure, the bisectors of $angle$ Q and $angle$ R meet at the point O then $angle$ QOR is

$90^{\circ} + \frac{1}{2} ∠ P$
$90^{\circ} + \frac{1}{2} ∠ R$
$90^{\circ} + \frac{1}{2} ∠ Q$
None of these

The correct answer is: $90 to the power of ring operator end exponent plus fraction numerator 1 over denominator 2 end fraction angle P$

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