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Maths-

General

Easy

Question

Integrating factor of $fraction numerator d y over denominator d x end fraction plus fraction numerator y over denominator x end fraction equals x to the power of 3 end exponent minus 3$ is

$x$
$\log x$
$- x$
$e^{x}$

The correct answer is: $x$

I.F. $equals e to the power of not stretchy integral p. d x end exponent$ Þ $e to the power of not stretchy integral fraction numerator 1 over denominator x end fraction d x end exponent equals e to the power of log subscript e end subscript invisible function application x end exponent equals x$ .

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