Maths-
General
Easy
Question
Let 
and 
be the areas of the triangular faces of tetrahedron and 
be the corresponding altitudes of the tetrahedron, then the minimum value of 
Given volume of the tetrahedron is 5cubic units.
- 240
- 225
- 160
- 180
Hint:
volume of a tetrahedron = Ah/3
The correct answer is: 180
240
We know that volume of a tetrahedron = A x h/3 = V = 5 cubic units.
A x h = 3 V
Summation of A x h from i , j = 1 to 4 will give us
(A1h1+A1h2+A1h3+A1h4 + A2h1 +A2h2+ …..) = 16x (Ah) = 16 x 3V = 48 x V = 48 x 5
= 240 cubic units.
volume of regular tetrahedron =
a3/6√2
volume of any tetrahedron = Ah/3
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