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Maths-

General

Easy

Question

Suppos ef, f' andf'' are continuous on[0, e] and that $f times x f times 1 equals 1 text and end text stretchy integral subscript 1 end subscript superscript c end superscript fraction numerator f left parenthesis x right parenthesis over denominator x to the power of 2 end exponent end fraction d x equals fraction numerator 1 over denominator 2 end fraction$ then the value of $stretchy integral subscript 1 end subscript superscript e end superscript f to the power of ´ ´ end exponent left parenthesis x right parenthesis l n invisible function application x d x text equals - end text$

0
1
2
noneofthese

The correct answer is: noneofthese

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