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Maths-

General

Easy

Question

The domain of the function $f open parentheses x close parentheses equals fraction numerator cos to the power of negative 1 end exponent invisible function application x over denominator left square bracket x right square bracket end fraction$ is

$[- 1, 0) \cup {1}$
[-1, 1]
[-1,A)
None of these

The correct answer is: $open square brackets negative 1 comma blank 0 close parentheses union left curly bracket 1 right curly bracket$

$because blank f open parentheses x close parentheses equals fraction numerator cos to the power of negative 1 end exponent invisible function application x over denominator left square bracket x right square bracket end fraction$
For $f left parenthesis x right parenthesis$ to be defined $negative 1 less or equal than x less or equal than 1$ and $open square brackets x close square brackets not equal to 0 rightwards double arrow x not an element of left square bracket 0 comma blank 1 right parenthesis$
$therefore$ Domain of $f left parenthesis x right parenthesis$ is $open square brackets negative 1 comma blank 0 close parentheses union left curly bracket 1 right curly bracket$ .

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