Maths-
SAT
Easy

Question

The equation p = 14.7 + 0.439d approximates the pressure p, in pounds per square  inch, exerted on a diver at a depth of d feet (ft) below the surface of the water. What  is the increase in depth that is necessary to increase the pressure by 1 pound  per square inch?

  1. fraction numerator 1 over denominator 0.439 end fraction f t
  2. fraction numerator 1 over denominator 14.7 end fraction f t
  3. 0.439 ft
  4. 14.7 ft

The correct answer is: fraction numerator 1 over denominator 0.439 end fraction f t


    p = 14.7 + 0.439 d
    1= 14.7 + 0.439d
    – 14 .7 = 0.439d
    - 13.7 = 0.439d
    negative fraction numerator 13.7 over denominator 0.439 end fraction equals d
    When p = 0         0 = 14.7 + 0.439 d
    fraction numerator negative 14.7 over denominator 0.439 end fraction equals d
    The increase =  fraction numerator negative 14.7 over denominator 0.439 end fraction minus open parentheses fraction numerator negative 13.7 over denominator 0.439 end fraction close parentheses equals fraction numerator 1 over denominator 0.439 end fraction

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