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Maths-

General

Easy

Question

The mode of the distribution

5
6
8
10

The correct answer is: 6

Since frequency is maximum for 6. \ Mode = 6.

Related Questions to study

If the mean of the distribution is 2.6, then the value of y is

If the mean of the distribution is 2.6, then the value of y is

The matrix $open square brackets table row 1 omega cell omega to the power of 2 end exponent end cell row omega cell omega to the power of 2 end exponent end cell 1 row cell omega to the power of 2 end exponent end cell 1 omega end table close square brackets$ is a -

The matrix $open square brackets table row 1 omega cell omega to the power of 2 end exponent end cell row omega cell omega to the power of 2 end exponent end cell 1 row cell omega to the power of 2 end exponent end cell 1 omega end table close square brackets$ is a -

If A = $open square brackets table row 1 0 row 1 1 end table close square brackets$ or $open square brackets table row 1 0 row 0 1 end table close square brackets$ , then which of the following holds of all n ≥ 1,

If A = $open square brackets table row 1 0 row 1 1 end table close square brackets$ or $open square brackets table row 1 0 row 0 1 end table close square brackets$ , then which of the following holds of all n ≥ 1,

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If $open square brackets table row alpha beta row gamma cell negative alpha end cell end table close square brackets$ is to be square root of two rowed unit matrix, then $alpha comma beta$ and $gamma$ should satisfy the relation

If $open square brackets table row alpha beta row gamma cell negative alpha end cell end table close square brackets$ is to be square root of two rowed unit matrix, then $alpha comma beta$ and $gamma$ should satisfy the relation

If A_r = $open parentheses table row r cell r minus 1 end cell row cell r minus 1 end cell r end table close parentheses$ where r is a natural number then |A₁| + |A₂| + |A₃| + ......+ |A₂₀₀₆| mustbe equal to

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If 3A = $open square brackets table row 1 2 2 row 2 1 cell negative 2 end cell row x 2 y end table close square brackets$ and A. A^t = I, then x + y equal to

If 3A = $open square brackets table row 1 2 2 row 2 1 cell negative 2 end cell row x 2 y end table close square brackets$ and A. A^t = I, then x + y equal to

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If D = diag [d₁, d₂, .....d_n] is a diagonal matrix with d_i ≠ 0, i = 1, 2, 3,......, n, then D^–1 is

If D = diag [d₁, d₂, .....d_n] is a diagonal matrix with d_i ≠ 0, i = 1, 2, 3,......, n, then D^–1 is

If the product of the matrix B = $open square brackets table row 2 6 4 row 1 0 1 row cell negative 1 end cell 1 cell negative 1 end cell end table close square brackets$ with a matrix A has inverse C = $open square brackets table row cell negative 1 end cell 0 1 row 1 1 3 row 2 0 2 end table close square brackets$ , then A^–1 equals-

If the product of the matrix B = $open square brackets table row 2 6 4 row 1 0 1 row cell negative 1 end cell 1 cell negative 1 end cell end table close square brackets$ with a matrix A has inverse C = $open square brackets table row cell negative 1 end cell 0 1 row 1 1 3 row 2 0 2 end table close square brackets$ , then A^–1 equals-

$MeC identical to straight C minus COCl not stretchy ⟶ with straight H subscript 2 plus text Lindlar's Catalyst end text on top$ (A) The product (A) is:

$MeC identical to straight C minus COCl not stretchy ⟶ with straight H subscript 2 plus text Lindlar's Catalyst end text on top$ (A) The product (A) is:

chemistry-General

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The value of x for which the matrix A = $open square brackets table row cell 2 divided by x end cell cell negative 1 end cell 2 row 1 x cell 2 x to the power of 2 end exponent end cell row 1 cell 1 divided by x end cell 2 end table close square brackets$ is singular is -

The value of x for which the matrix A = $open square brackets table row cell 2 divided by x end cell cell negative 1 end cell 2 row 1 x cell 2 x to the power of 2 end exponent end cell row 1 cell 1 divided by x end cell 2 end table close square brackets$ is singular is -

If A is an orthogonal matrix, then |A| is-

If A is an orthogonal matrix, then |A| is-

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The inverse of a skew symmetric matrix (if it exists) is -

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Let A = $open square brackets table row 0 cell 2 y end cell z row x y cell negative z end cell row x cell negative y end cell z end table close square brackets$ and A'. A = I, then the value of x² + y² + z² is-

Let A = $open square brackets table row 0 cell 2 y end cell z row x y cell negative z end cell row x cell negative y end cell z end table close square brackets$ and A'. A = I, then the value of x² + y² + z² is-

If A = $open square brackets table row 1 0 row 1 1 end table close square brackets$ or $open square brackets table row 1 0 row 0 1 end table close square brackets$ , then which of the following holds for all n ≥ 1, by principle of mathematical induction

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If $open square brackets table row alpha beta row gamma cell negative alpha end cell end table close square brackets$ is to be square root of two rowed unit matrix, then $alpha comma beta text and end text gamma$ should satisfy the relation-

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