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Chemistry-

General

Easy

Question

The molar solubility in mol.lit^-1 of a sparingly soluble salt MX₄ is S. The corresponding solubility product K_sp is given by the relation.

$S = {(K_{s p} / 128)}^{1 / 4}$
$S = {(218 K_{s p})}^{1 / 4}$
$S = {(256 K_{s p})}^{1 / 5}$
$S = {(K_{s p} / 256)}^{1 / 5}$

The correct answer is: $S equals open parentheses K subscript s p end subscript divided by 256 close parentheses to the power of 1 divided by 5 end exponent$

Related Questions to study

Among the following statements a) If two salts have equal solubility then their solubility products are equal. b) BaSO₄ in more soluble in water than in dil.H₂SO₄ . c) When KI is added to PbI₂ , then the $[{P b}^{2 +}]$ decreases d) In any solution containing AgCl , the value of $[{A g}^{+}] [{C l}^{-}]$ is constant at constant temperature.

Among the following statements a) If two salts have equal solubility then their solubility products are equal. b) BaSO₄ in more soluble in water than in dil.H₂SO₄ . c) When KI is added to PbI₂ , then the $[{P b}^{2 +}]$ decreases d) In any solution containing AgCl , the value of $[{A g}^{+}] [{C l}^{-}]$ is constant at constant temperature.

chemistry-General

In which of the following, the solubility of AgCl will be maximum ?

In which of the following, the solubility of AgCl will be maximum ?

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At 298 K , the K_sp value of Fe(OH)₃ in aqueous solution is $3.8 \times 10^{- 38}$ The solubility of Fe³⁺ ions will increase when

At 298 K , the K_sp value of Fe(OH)₃ in aqueous solution is $3.8 \times 10^{- 38}$ The solubility of Fe³⁺ ions will increase when

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In the following reaction , $A g C l + K I \to K C l + A g I$ . As KI is added , the equilibrium is shifted towards right giving more AgI precipitate , because

In the following reaction , $A g C l + K I \to K C l + A g I$ . As KI is added , the equilibrium is shifted towards right giving more AgI precipitate , because

chemistry-General

Which of the following is most soluble ?

Which of the following is most soluble ?

chemistry-General

Which of the following has the lowest value of K_sp at 25°C ?

Which of the following has the lowest value of K_sp at 25°C ?

chemistry-General

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The correct representation for solubility product of SnS₂ is

The correct representation for solubility product of SnS₂ is

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Which pair will show common ion effect ?

Which pair will show common ion effect ?

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Out of Ca²⁺ , Al³⁺ , Bi³⁺ , Mg²⁺ and Zn²⁺ the reagents NH₄Cl and aqueous NH₃ will precipitate

Out of Ca²⁺ , Al³⁺ , Bi³⁺ , Mg²⁺ and Zn²⁺ the reagents NH₄Cl and aqueous NH₃ will precipitate

chemistry-General

parallel

The addition of NaCl to AgCl decreases the solubility of AgCl , because

The addition of NaCl to AgCl decreases the solubility of AgCl , because

chemistry-General

How do we differentiate between Fe³⁺ and Cr³⁺ in group III ?

How do we differentiate between Fe³⁺ and Cr³⁺ in group III ?

chemistry-General

In qualitative analysis , to identify the IIA group sulphides , HCl is added to salt solution before the addition of H₂S . Because

In qualitative analysis , to identify the IIA group sulphides , HCl is added to salt solution before the addition of H₂S . Because

chemistry-General

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If $c o s invisible function application alpha plus 2 c o s invisible function application beta plus 3 c o s invisible function application gamma equals s i n invisible function application alpha plus 2 s i n invisible function application beta plus 3 s i n invisible function application gamma equals 0$ then $s i n invisible function application 3 alpha plus 8 s i n invisible function application 3 beta plus 27 s i n invisible function application 3 gamma equals$

If $c o s invisible function application alpha plus 2 c o s invisible function application beta plus 3 c o s invisible function application gamma equals s i n invisible function application alpha plus 2 s i n invisible function application beta plus 3 s i n invisible function application gamma equals 0$ then $s i n invisible function application 3 alpha plus 8 s i n invisible function application 3 beta plus 27 s i n invisible function application 3 gamma equals$

$1 comma alpha subscript 1 end subscript comma alpha subscript 2 end subscript comma alpha subscript 3 horizontal ellipsis horizontal ellipsis end subscript alpha subscript n minus 1 end subscript$ are the n^th roots of unity and n is an even natural number, then $open parentheses 1 plus alpha subscript 1 end subscript close parentheses open parentheses 1 plus alpha subscript 2 end subscript close parentheses open parentheses 1 plus alpha subscript 3 end subscript close parentheses horizontal ellipsis horizontal ellipsis open parentheses 1 plus alpha subscript n minus 1 end subscript close parentheses equals$

$1 comma alpha subscript 1 end subscript comma alpha subscript 2 end subscript comma alpha subscript 3 horizontal ellipsis horizontal ellipsis end subscript alpha subscript n minus 1 end subscript$ are the n^th roots of unity and n is an even natural number, then $open parentheses 1 plus alpha subscript 1 end subscript close parentheses open parentheses 1 plus alpha subscript 2 end subscript close parentheses open parentheses 1 plus alpha subscript 3 end subscript close parentheses horizontal ellipsis horizontal ellipsis open parentheses 1 plus alpha subscript n minus 1 end subscript close parentheses equals$

Statement-I : If $x subscript n end subscript equals c o s invisible function application open parentheses pi divided by 2 to the power of n end exponent close parentheses plus i s i n invisible function application open parentheses pi divided by 2 to the power of n end exponent close parentheses$ then $x subscript 1 end subscript times x subscript 2 end subscript times x subscript 3 end subscript horizontal ellipsis horizontal ellipsis equals negative 1$
Statement-II : $x subscript n end subscript equals c o s invisible function application open parentheses pi divided by 4 to the power of n end exponent close parentheses plus i s i n invisible function application open parentheses pi divided by 4 to the power of n end exponent close parentheses$ then $x subscript 1 end subscript times x subscript 2 end subscript times x subscript 3 end subscript horizontal ellipsis horizontal ellipsis infinity equals negative 1$

Statement-I : If $x subscript n end subscript equals c o s invisible function application open parentheses pi divided by 2 to the power of n end exponent close parentheses plus i s i n invisible function application open parentheses pi divided by 2 to the power of n end exponent close parentheses$ then $x subscript 1 end subscript times x subscript 2 end subscript times x subscript 3 end subscript horizontal ellipsis horizontal ellipsis equals negative 1$
Statement-II : $x subscript n end subscript equals c o s invisible function application open parentheses pi divided by 4 to the power of n end exponent close parentheses plus i s i n invisible function application open parentheses pi divided by 4 to the power of n end exponent close parentheses$ then $x subscript 1 end subscript times x subscript 2 end subscript times x subscript 3 end subscript horizontal ellipsis horizontal ellipsis infinity equals negative 1$

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