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Question

The number of divisors of $3 cross times 7 to the power of 3 end exponent comma blank 7 cross times 11 to the power of 2 end exponent$ and $2 cross times 61$ are in

AP
GP
HP
None of these

The correct answer is: AP

The number of divisors of $3 cross times 7 to the power of 3 end exponent$ = (1+1) (3+1) =8
The number of divisors of $7 cross times 11 to the power of 2 end exponent equals open parentheses 1 plus 1 close parentheses open parentheses 2 plus 1 close parentheses equals 6$
And the number of divisors of $2 cross times 61 equals open parentheses 1 plus 1 close parentheses open parentheses 1 plus 1 close parentheses equals 4$
$rightwards double arrow 8 comma blank 6 comma blank 4 blank$ are in AP with common difference-2

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