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Maths-

General

Easy

Question

The symbolic form of logic of the circuit given below is

$[(p \land q^{})]$ ∨p'∧q'/>
$[p \lor (q^{})]$ ∧p'∨q'/>
$[(p \land p^{})]$ ∨q'∧q'/>
$[p \land (q^{})]$ ∨p'∨q'/>

The correct answer is: $open square brackets p logical and open parentheses q to the power of ´ end exponent logical or p to the power of ´ end exponent close parentheses close square brackets logical or q$

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