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Physics-

General

Easy

Question

A 20 $mu F$ capacitor is connected to 45 V battery through a circuit whose resistance is 2000 $capital omega.$ What is the final charge on the capacitor?

$9 \times 10^{- 4} C$
$9.154 \times 10^{- 4} C$
$9.8 \times 10^{- 4} C$
None of these

The correct answer is: $9 cross times 10 to the power of negative 4 end exponent C$

We know that in steady state the capacitor behaves like as an open circuit $i e$ , capacitor will not pass the current.

So, the potential difference across the capacitor = 45 V
Hence , the final charge on the capacitor is
$q equals C V$
Here , $C equals 20 mu F comma blank V equals 45 blank V$
$therefore blank q equals 20 cross times 10 to the power of negative 6 end exponent cross times 45$
or $blank q equals 900 cross times 10 to the power of negative 6 end exponent$
or $blank q equals 9 cross times 10 to the power of negative 4 end exponent C$

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