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Physics-

General

Easy

Question

A ball of mass m is connected to two rubber bands of length L each, under tension T as shown in the figure. The entire system is placed on a smooth horizontal surface. the ball is displaced by a small distance y perpendicular to the length of the rubber bands. Assuming that tension in rubber bands doesn't change the angular frequency of oscillations performed by the ball is

$\sqrt{\frac{T}{m L}}$
$\sqrt{\frac{2 T}{m L}}$
$\sqrt{\frac{T}{2 m L}}$
$\sqrt{\frac{m L}{2 T}}$

The correct answer is: $square root of fraction numerator 2 text end text T over denominator text end text m L end fraction end root$

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