Physics-
General
Easy

Question

A block of mass m is pulled by a string acts which passes over a smooth pulley P fitted with the wedge of mass M. A horizontal force F=mg acts on the string. If the string is massless and inextensible, assuming frictionless contacting surfaces and theta equals c o s to the power of negative 1 end exponent invisible function application fraction numerator 4 over denominator 5 end fraction then

  1. N equals fraction numerator 4 over denominator 5 end fraction m g semicolon N equals reaction on the block    
  2. a subscript 1 end subscript equals fraction numerator 17 over denominator 25 end fraction g leftwards arrow semicolon a subscript 1 end subscript equals acceleration of m    
  3. N to the power of ' end exponent greater than 25 m g semicolon N to the power of ' end exponent equals>25mg;N'='/> reaction by the wedge from groove    
  4. a subscript 2 end subscript equals fraction numerator g over denominator 2 end fraction semicolon a subscript 2 end subscript equals acceleration of M    

The correct answer is: N to the power of ´ end exponent greater than 25 m g semicolon N to the power of ´ end exponent equals reaction by the wedge from groove

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