Physics-
General
Easy

Question

A block of mass m, lying on a horizontal plane, is acted upon by a horizontal force P and another force Q, inclined at an angle Q to the vertical. The block will remain in equilibrium if the coefficient of friction between block and the surface is (P > Q)

  1. left parenthesis P s i n invisible function application theta minus Q right parenthesis divided by left parenthesis m g minus c o s invisible function application theta right parenthesis    
  2. left parenthesis P minus Q s i n invisible function application theta right parenthesis divided by left parenthesis m g plus Q c o s invisible function application theta right parenthesis    
  3. left parenthesis P c o s invisible function application theta plus Q right parenthesis divided by left parenthesis m g minus Q C o s invisible function application theta right parenthesis    
  4. left parenthesis P plus Q S i n invisible function application theta right parenthesis divided by left parenthesis m g plus Q c o s invisible function application theta right parenthesis    

The correct answer is: left parenthesis P minus Q s i n invisible function application theta right parenthesis divided by left parenthesis m g plus Q c o s invisible function application theta right parenthesis


    f equals mu N equals mu left parenthesis m g plus Q C o s invisible function application theta right parenthesis
    F subscript n e t end subscript equals P minus Q Sin invisible function application theta
    For equilibrium we have
    mu left parenthesis m g plus Q c o s invisible function application theta right parenthesis equals P minus Q s i n invisible function application theta
    mu equals fraction numerator P minus Q Sin invisible function application theta over denominator m g plus Q cos invisible function application theta end fraction

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