Physics-
General
Easy

Question

A conductor ABOCD moves along its bisector with a velocity of 1 m/s through a perpendicular magnetic field of 1 wb/m2, as shown in fig. If all the four sides are of 1m length each, then the induced emf between points A and D is

  1. 0    
  2. 1.41 volt    
  3. 0.71 volt    
  4. None of the above    

The correct answer is: 1.41 volt


    There is no induced emf in the part AB and CD because they are moving along their length while emf induced between B and C i.e. between A and D can be calculated as follows

    Induced emf between B and C = Induced emf between A and B = B v left parenthesis square root of 2 l right parenthesis equals 1 cross times 1 cross times 1 cross times square root of 2 equals 1.41 v o l t.

    Related Questions to study

    General
    physics-

    A square metallic wire loop of side 0.1 m and resistance of 1W is moved with a constant velocity in a magnetic field of 2 wb/m2 as shown in figure. The magnetic field is perpendicular to the plane of the loop, loop is connected to a network of resistances. What should be the velocity of loop so as to have a steady current of 1mA in loop

    A square metallic wire loop of side 0.1 m and resistance of 1W is moved with a constant velocity in a magnetic field of 2 wb/m2 as shown in figure. The magnetic field is perpendicular to the plane of the loop, loop is connected to a network of resistances. What should be the velocity of loop so as to have a steady current of 1mA in loop

    physics-General
    General
    physics-

    A conducting wire frame is placed in a magnetic field which is directed into the paper. The magnetic field is increasing at a constant rate. The directions of induced current in wires AB and CD are

    A conducting wire frame is placed in a magnetic field which is directed into the paper. The magnetic field is increasing at a constant rate. The directions of induced current in wires AB and CD are

    physics-General
    General
    physics-

    As shown in the figure a metal rod makes contact and complete the circuit. The circuit is perpendicular to the magnetic field with B equals 0.15 t e s l a. If the resistance is 3 capital omega, force needed to move the rod as indicated with a constant speed of 2 m divided by s e c is

    As shown in the figure a metal rod makes contact and complete the circuit. The circuit is perpendicular to the magnetic field with B equals 0.15 t e s l a. If the resistance is 3 capital omega, force needed to move the rod as indicated with a constant speed of 2 m divided by s e c is

    physics-General
    parallel
    General
    physics-

    As shown in the figure, P and Q are two coaxial conducting loops separated by some distance. When the switch S is closed, a clockwise current I subscript P end subscript flows in P (as seen by E) and an induced current I subscript Q subscript 1 end subscript end subscript flows in Q. The switch remains closed for a long time. When S is opened, a current I subscript Q subscript 2 end subscript end subscript flows in Q. Then the directions of I subscript Q subscript 1 end subscript end subscript and I subscript Q subscript 2 end subscript end subscript (as seen by E) are

    As shown in the figure, P and Q are two coaxial conducting loops separated by some distance. When the switch S is closed, a clockwise current I subscript P end subscript flows in P (as seen by E) and an induced current I subscript Q subscript 1 end subscript end subscript flows in Q. The switch remains closed for a long time. When S is opened, a current I subscript Q subscript 2 end subscript end subscript flows in Q. Then the directions of I subscript Q subscript 1 end subscript end subscript and I subscript Q subscript 2 end subscript end subscript (as seen by E) are

    physics-General
    General
    Maths-

    A particle moves along a line by s equals t to the power of 3 end exponent minus 9 t to the power of 2 end exponent plus 24 t then S is decreasing when t element of

    A particle moves along a line by s equals t to the power of 3 end exponent minus 9 t to the power of 2 end exponent plus 24 t then S is decreasing when t element of

    Maths-General
    General
    maths-

    Assertion: f(x) = ln open vertical bar fraction numerator 1 plus tan invisible function application x over denominator 1 minus tan invisible function application x end fraction close vertical bar is an odd function.
    Reason: Let f be a function with domain D such that
    i) x element of D rightwards double arrow – x element of D
    ii) f(–x) = – f(x) and
    iii) f (0) = 0 or f (0) is not defined
    Then the function f(x) is an odd function

    Assertion: f(x) = ln open vertical bar fraction numerator 1 plus tan invisible function application x over denominator 1 minus tan invisible function application x end fraction close vertical bar is an odd function.
    Reason: Let f be a function with domain D such that
    i) x element of D rightwards double arrow – x element of D
    ii) f(–x) = – f(x) and
    iii) f (0) = 0 or f (0) is not defined
    Then the function f(x) is an odd function

    maths-General
    parallel
    General
    physics-

    A conducting rod of length 2l is rotating with constant angular speed w about its perpendicular bisector. A uniform magnetic field Error converting from MathML to accessible text. exists parallel to the axis of rotation. The e.m.f. induced between two ends of the rod is

    A conducting rod of length 2l is rotating with constant angular speed w about its perpendicular bisector. A uniform magnetic field Error converting from MathML to accessible text. exists parallel to the axis of rotation. The e.m.f. induced between two ends of the rod is

    physics-General
    General
    physics-

    A metallic square loop ABCD is moving in its own plane with velocity v in a uniform magnetic field perpendicular to its plane as shown in the figure. An electric field is induced

    A metallic square loop ABCD is moving in its own plane with velocity v in a uniform magnetic field perpendicular to its plane as shown in the figure. An electric field is induced

    physics-General
    General
    physics-

    Two circular coils can be arranged in any of the three situations shown in the figure. Their mutual inductance will be

    Two circular coils can be arranged in any of the three situations shown in the figure. Their mutual inductance will be

    physics-General
    parallel
    General
    physics-

    A uniform but time-varying magnetic field B(t) exists in a circular region of radius a and is directed into the plane of the paper, as shown. The magnitude of the induced electric field at point P at a distance r from the centre of the circular region

    A uniform but time-varying magnetic field B(t) exists in a circular region of radius a and is directed into the plane of the paper, as shown. The magnitude of the induced electric field at point P at a distance r from the centre of the circular region

    physics-General
    General
    maths-

    With the usual meaning for a, b, c and s if straight capital delta be the area of a triangle then the error in straight capital delta resulting from a small error in the measurement of c, is

    With the usual meaning for a, b, c and s if straight capital delta be the area of a triangle then the error in straight capital delta resulting from a small error in the measurement of c, is

    maths-General
    General
    physics-

    Consider the situation shown in the figure. The wire AB is sliding on the fixed rails with a constant velocity. If the wire AB is replaced by semicircular wire, the magnitude of the induced current will

    Consider the situation shown in the figure. The wire AB is sliding on the fixed rails with a constant velocity. If the wire AB is replaced by semicircular wire, the magnitude of the induced current will

    physics-General
    parallel
    General
    physics-

    A thin semicircular conducting ring of radius R is falling with its plane vertical in a horizontal magnetic induction B. At the position MNQ, the speed of the ring is V and the potential difference developed across the ring is

    A thin semicircular conducting ring of radius R is falling with its plane vertical in a horizontal magnetic induction B. At the position MNQ, the speed of the ring is V and the potential difference developed across the ring is

    physics-General
    General
    physics-

    An electron moves along the line AB, which lies in the same plane as a circular loop of conducting wires as shown in the diagram. What will be the direction of current induced if any, in the loop

    An electron moves along the line AB, which lies in the same plane as a circular loop of conducting wires as shown in the diagram. What will be the direction of current induced if any, in the loop

    physics-General
    General
    physics-

    In the circuit shown switch k2 is open and switch k1 is closed at t = 0. At time t = to­ switch k1 is opened and switch k2 is simultaneously closed. The variation of inductor current with time is

    In the circuit shown switch k2 is open and switch k1 is closed at t = 0. At time t = to­ switch k1 is opened and switch k2 is simultaneously closed. The variation of inductor current with time is

    physics-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.