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General
Easy
Question
A hollow vertical cylinder of radius R is rotated with angular velocity w about an axis through its center. What is the minimum coefficient of static friction necessary to keep the mass M suspended on the inside of the cylinder as it rotates?
The correct answer is:
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Physics-
At time t = 0, N1 nuclei of decay constant 
& N2 nuclei of decay constant 
are mixed . The decay rate of the mixture is :
At time t = 0, N1 nuclei of decay constant & N2 nuclei of decay constant are mixed . The decay rate of the mixture is :
Physics-General
Physics-
In an 
-decay the Kinetic energy of particle is 48 MeV and Q-value of the reaction is 50 MeV. The mass number of the mother nucleus is: (Assume that daughter nucleus is in ground state)
In an -decay the Kinetic energy of particle is 48 MeV and Q-value of the reaction is 50 MeV. The mass number of the mother nucleus is: (Assume that daughter nucleus is in ground state)
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Physics-
The maximum speed of a car on a road–turn of radius 30 m, if the coefficient of friction between the types and the road is 0.4, will be:
The maximum speed of a car on a road–turn of radius 30 m, if the coefficient of friction between the types and the road is 0.4, will be:
Physics-General
Physics-
Out of the following, the only pair that does not have identical dimensions is:
Out of the following, the only pair that does not have identical dimensions is:
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Physics-
The unit of e.m.f. is:
The unit of e.m.f. is:
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Curie is a unit of:
Curie is a unit of:
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Physics-
The dimensions of shear modulus are:
The dimensions of shear modulus are:
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Physics-
Which physical quantities have the same dimension:
Which physical quantities have the same dimension:
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Physics-
Dimensions of magnetic field intensity is:
Dimensions of magnetic field intensity is:
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Physics-
The potential energy of a harmonic oscillator of mass 2 kg in its mean position is 5J. If its total energy is 9J, and its amplitude is 0.01 m, its time period would be:
The potential energy of a harmonic oscillator of mass 2 kg in its mean position is 5J. If its total energy is 9J, and its amplitude is 0.01 m, its time period would be:
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physics-
In the figure, the block of mass m, attached to the spring of stiffness k is in contact with the completely elastic wall, and the compression in the spring is 'e'. The spring is compressed further by 'e' by displacing the block towards left and is then released. If the collision between the block and the wall is completely elastic then the time period of oscillations of the block will be:
In the figure, the block of mass m, attached to the spring of stiffness k is in contact with the completely elastic wall, and the compression in the spring is 'e'. The spring is compressed further by 'e' by displacing the block towards left and is then released. If the collision between the block and the wall is completely elastic then the time period of oscillations of the block will be:
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Time period of small oscillation (in a vertical plane normal to the plane of strings) of the bob in the arrangement shown will be:
Time period of small oscillation (in a vertical plane normal to the plane of strings) of the bob in the arrangement shown will be:
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Physics-
A spring mass system preforms S.H.M. If the mass is doubled keeping amplitude same, then the total energy of S.H.M. will become:
A spring mass system preforms S.H.M. If the mass is doubled keeping amplitude same, then the total energy of S.H.M. will become:
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physics-
Two blocks of masses 3 kg and 6 kg rest on a horizontal smooth surface. The 3 kg block is attached to a spring with a force constant k = 900 Nm-1 which is compressed 2 m from beyond the equilibrium position. The 6 kg mass is at rest at 1m from mean position.3kg mass strikes the 6 kg mass and the two stick together
Two blocks of masses 3 kg and 6 kg rest on a horizontal smooth surface. The 3 kg block is attached to a spring with a force constant k = 900 Nm-1 which is compressed 2 m from beyond the equilibrium position. The 6 kg mass is at rest at 1m from mean position.3kg mass strikes the 6 kg mass and the two stick together
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Physics-
The potential energy of a particle of mass 0.1kg, moving along x-axis, is given by U = 5x(x-4)J where x is in metres. It can be concluded that
The potential energy of a particle of mass 0.1kg, moving along x-axis, is given by U = 5x(x-4)J where x is in metres. It can be concluded that
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