Physics-
General
Easy

Question

A large mass M hangs stationary at the end of a light string that passes through a smooth fixed tube to a small mass m that moves around in horizontal circular path. If l is the length of the string from m to the top end of the tube and theta is angle between this part and vertical part of the string as shown in the fig, then time taken by m to complete one circle is equal to

  1. 2 pi square root of fraction numerator l over denominator g s i n invisible function application theta end fraction end root    
  2. 2 pi square root of fraction numerator l over denominator g c o s invisible function application theta end fraction end root    
  3. 2 pi square root of fraction numerator m l over denominator g M s i n invisible function application theta end fraction end root    
  4. 2 pi square root of fraction numerator l m over denominator g M end fraction end root    

The correct answer is: 2 pi square root of fraction numerator l m over denominator g M end fraction end root

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