A monatomic ideal gas is used as the working substance for the Carnot cycle shown in the figure. Processes AB and CD are isothermal, while processes BC and DA are adiabatic. During process AB, 400 J of work is done by the gas on the surroundings. How much heat is expelled by the gas during process CD?

Maths-

The two points A and B in a plane are such that for all points P lies on circle satisfied $P A divided by P B equals k$ , then k will not be equal to

So here we have given the two points A and B in a plane are such that for all points P lies on circle satisfied $P A divided by P B equals k$ . We can also use equation of circle to find the answer. So here the correct option is none of these.

The two points A and B in a plane are such that for all points P lies on circle satisfied $P A divided by P B equals k$ , then k will not be equal to

Maths-General

Maths-

A circle touches the x-axis and also touches the circle with centre at (0, 3) and radius. The locus of the centre of the circle is

So here we have given to find the locus is in which form. We used the concept of circles and solved the question. We can also use equation of circle to find the answer. So the locus is x²-10y+5=0, this is the representation of parabola, so correct answer is parabola.

A circle touches the x-axis and also touches the circle with centre at (0, 3) and radius. The locus of the centre of the circle is

Maths-General

Maths-

If d is the distance between the centres of two circles, $r subscript 1 comma r subscript 2$ are their radii and $d equals r subscript 1 plus r subscript 2$ , then

For such questions, we have to see how the cricles are with respect to each other to find the distance between the centers.

If d is the distance between the centres of two circles, $r subscript 1 comma r subscript 2$ are their radii and $d equals r subscript 1 plus r subscript 2$ , then

Maths-General

For such questions, we have to see how the cricles are with respect to each other to find the distance between the centers.

Assertion (A): The curve $y equals x to the power of 2 end exponent minus 6 x plus 9$ touches the x-axis.
Reason(R): $y equals a x to the power of 2 end exponent plus b x plus c$ touches the x-axis if $capital delta equals b to the power of 2 end exponent minus 4 a c equals 0$

Assertion (A): $f left parenthesis x right parenthesis equals a x to the power of 2 end exponent plus b x plus c comma blank f o r blank a left parenthesis not equal to 0 right parenthesis comma b comma c element of R$ When a>0 and $b to the power of 2 end exponent minus 4 a c less than 0 comma f left parenthesis x right parenthesis equals 0$ has complex roots.
Reason(R): The graph of $f left parenthesis x right parenthesis equals a x to the power of 2 end exponent plus b x plus c$ cuts x-axis.

In an ellipse $9 x to the power of 2 end exponent plus 5 y to the power of 2 end exponent equals 45$ , the distance between the foci is

If $P identical to left parenthesis x comma y right parenthesis$ , $F subscript 1 end subscript identical to left parenthesis 3 comma 0 right parenthesis$ , $F subscript 2 end subscript identical to left parenthesis negative 3 comma 0 right parenthesis$ and $16 x to the power of 2 end exponent plus 25 y to the power of 2 end exponent equals 400$ , then $P F subscript 1 end subscript plus P F subscript 2 end subscript$ equals

chemistry-

Arrange the following in decreasing order of their solubility in water

chemistry-General

chemistry-

Which have maximum solubility in water, for nearly same molecular weight compounds

chemistry-General