Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Physics-

General

Easy

Question

A plank of mass M is placed over smooth inclined plane and a sphere is also placed over the plank. Friction is sufficient between sphere and plank. If plank and sphere are released from rest, the frictional force on sphere is:

up the plane
down the plane
horizontal
zero

The correct answer is: zero

Related Questions to study

Portion AB of the wedge shown in figure is rough and BC is smooth. A solid cylinder rolls without slipping from A to B. The ratio of translational kinetic energy to rotational kinetic energy, when the cylinder reaches point C is :

Portion AB of the wedge shown in figure is rough and BC is smooth. A solid cylinder rolls without slipping from A to B. The ratio of translational kinetic energy to rotational kinetic energy, when the cylinder reaches point C is :

physics-General

Inner and outer radii of a spool are r and R respectively. A thread is wound over its inner surface and placed over a rough horizontal surface. Thread is pulled by a force F as shown in fig. then in case of pure rolling

Inner and outer radii of a spool are r and R respectively. A thread is wound over its inner surface and placed over a rough horizontal surface. Thread is pulled by a force F as shown in fig. then in case of pure rolling

physics-General

Two identical circular loops are moving with same kinetic energy one rolls & other slides. The ratio of their speed is :

Two identical circular loops are moving with same kinetic energy one rolls & other slides. The ratio of their speed is :

physics-General

parallel

A disc of radius R is rolling purely on a flat horizontal surface, with a constant angular velocity. The angle between the velocity and acceleration vectors of point P is

A disc of radius R is rolling purely on a flat horizontal surface, with a constant angular velocity. The angle between the velocity and acceleration vectors of point P is

physics-General

A thin rod of length L is placed at angle $theta$ to vertical on a frictionless horizontal floor and released. If the center of mass has acceleration = A, and the rod an angular acceleration = $alpha$ at initial moment, then

A thin rod of length L is placed at angle $theta$ to vertical on a frictionless horizontal floor and released. If the center of mass has acceleration = A, and the rod an angular acceleration = $alpha$ at initial moment, then

physics-General

If $f$ is a real-valued differentiable function satisfying $vertical line f left parenthesis x right parenthesis minus f left parenthesis y right parenthesis vertical line less or equal than left parenthesis x minus y right parenthesis to the power of 2 end exponent comma x comma y element of R$ and f(0)=0, then f(1) equals

If $f$ is a real-valued differentiable function satisfying $vertical line f left parenthesis x right parenthesis minus f left parenthesis y right parenthesis vertical line less or equal than left parenthesis x minus y right parenthesis to the power of 2 end exponent comma x comma y element of R$ and f(0)=0, then f(1) equals

parallel

If f(x) = $open curly brackets table row cell fraction numerator x to the power of 2 end exponent minus 1 over denominator x to the power of 2 end exponent plus 1 end fraction end cell cell comma 0 less than x less or equal than 2 end cell row cell fraction numerator 1 over denominator 4 end fraction open parentheses x to the power of 3 end exponent minus x to the power of 2 end exponent close parentheses end cell cell comma 2 less than x less or equal than 3 end cell row cell fraction numerator 9 over denominator 4 end fraction left parenthesis vertical line x minus 4 vertical line plus vertical line 2 minus x vertical line right parenthesis comma end cell cell 3 less than x less than 4 end cell end table comma close$ then:

If f(x) = $open curly brackets table row cell fraction numerator x to the power of 2 end exponent minus 1 over denominator x to the power of 2 end exponent plus 1 end fraction end cell cell comma 0 less than x less or equal than 2 end cell row cell fraction numerator 1 over denominator 4 end fraction open parentheses x to the power of 3 end exponent minus x to the power of 2 end exponent close parentheses end cell cell comma 2 less than x less or equal than 3 end cell row cell fraction numerator 9 over denominator 4 end fraction left parenthesis vertical line x minus 4 vertical line plus vertical line 2 minus x vertical line right parenthesis comma end cell cell 3 less than x less than 4 end cell end table comma close$ then:

where represents the integral part function, then:

where represents the integral part function, then:

Which of the following function(s) has/have removable discontinuity at

Which of the following function(s) has/have removable discontinuity at

parallel

Consider the function f(x)= $open square brackets table row cell x left curly bracket x right curly bracket plus 1 end cell cell 0 less or equal than x less than 1 end cell row cell 2 minus left curly bracket x right curly bracket end cell cell 1 less or equal than x less or equal than 2 end cell end table close$ where {x} denotes the fractional part function. Which one of the following statements is NOT correct?

Consider the function f(x)= $open square brackets table row cell x left curly bracket x right curly bracket plus 1 end cell cell 0 less or equal than x less than 1 end cell row cell 2 minus left curly bracket x right curly bracket end cell cell 1 less or equal than x less or equal than 2 end cell end table close$ where {x} denotes the fractional part function. Which one of the following statements is NOT correct?

Statement-I : If $a subscript 1 end subscript comma a subscript 2 end subscript comma a subscript 3 end subscript comma horizontal ellipsis horizontal ellipsis a subscript n end subscript greater than 0$ , then $l i m subscript x rightwards arrow infinity end subscript open curly brackets fraction numerator a subscript 1 end subscript superscript 1 divided by x end superscript plus a subscript 2 end subscript superscript 1 divided by x end superscript plus a subscript 3 end subscript superscript 1 divided by x end superscript plus horizontal ellipsis.. plus a subscript n end subscript superscript 1 divided by x end superscript over denominator n end fraction close curly brackets to the power of n x end exponent equals product subscript i equals 1 end subscript superscript n end superscript a subscript n end subscript$

Statement-I : If $a subscript 1 end subscript comma a subscript 2 end subscript comma a subscript 3 end subscript comma horizontal ellipsis horizontal ellipsis a subscript n end subscript greater than 0$ , then $l i m subscript x rightwards arrow infinity end subscript open curly brackets fraction numerator a subscript 1 end subscript superscript 1 divided by x end superscript plus a subscript 2 end subscript superscript 1 divided by x end superscript plus a subscript 3 end subscript superscript 1 divided by x end superscript plus horizontal ellipsis.. plus a subscript n end subscript superscript 1 divided by x end superscript over denominator n end fraction close curly brackets to the power of n x end exponent equals product subscript i equals 1 end subscript superscript n end superscript a subscript n end subscript$

$L i m subscript x rightwards arrow 0 end subscript invisible function application fraction numerator left parenthesis 1 minus c o s invisible function application 2 x right parenthesis left parenthesis 3 plus c o s invisible function application x right parenthesis over denominator x t a n invisible function application 4 x end fraction$ is equal to

$L i m subscript x rightwards arrow 0 end subscript invisible function application fraction numerator left parenthesis 1 minus c o s invisible function application 2 x right parenthesis left parenthesis 3 plus c o s invisible function application x right parenthesis over denominator x t a n invisible function application 4 x end fraction$ is equal to

parallel

$l i m subscript s rightwards arrow pi divided by 2 end subscript fraction numerator left square bracket 1 minus t a n invisible function application x divided by 2 right square bracket left square bracket 1 minus s i n invisible function application x right square bracket over denominator left square bracket 1 plus t a n invisible function application x divided by 2 right square bracket left square bracket pi minus 2 x right square bracket to the power of 3 end exponent end fraction$ is equal to-

$l i m subscript s rightwards arrow pi divided by 2 end subscript fraction numerator left square bracket 1 minus t a n invisible function application x divided by 2 right square bracket left square bracket 1 minus s i n invisible function application x right square bracket over denominator left square bracket 1 plus t a n invisible function application x divided by 2 right square bracket left square bracket pi minus 2 x right square bracket to the power of 3 end exponent end fraction$ is equal to-

Statement $negative I colon$ The sum of the series 1+(1+2+4)+(4+6+9)+(9+12+16)+…+(361+380+400) is 8000.
Statement - II : $sum subscript k equals 1 end subscript superscript n end superscript open parentheses k to the power of 3 end exponent minus left parenthesis k minus 1 right parenthesis to the power of 3 end exponent close parentheses equals n to the power of 3 end exponent$ , for any natural number n.

Statement $negative I colon$ The sum of the series 1+(1+2+4)+(4+6+9)+(9+12+16)+…+(361+380+400) is 8000.
Statement - II : $sum subscript k equals 1 end subscript superscript n end superscript open parentheses k to the power of 3 end exponent minus left parenthesis k minus 1 right parenthesis to the power of 3 end exponent close parentheses equals n to the power of 3 end exponent$ , for any natural number n.

If in a frequently distribution, the mean and median are 21 and 22 respectively, then its mode is approximately.

If in a frequently distribution, the mean and median are 21 and 22 respectively, then its mode is approximately.

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.