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Easy

Question

A steady current is set up in a cubic network composed of wires of equal resistance and length d as shown in figure. What is the magnetic field at the centre of cube P due to the cubic network ?

  1. fraction numerator mu subscript 0 end subscript over denominator 4 pi end fraction fraction numerator 2 I over denominator d end fraction    
  2. fraction numerator mu subscript 0 end subscript over denominator 4 pi end fraction fraction numerator 3 I over denominator square root of 2 d end fraction    
  3. 0    
  4. fraction numerator mu subscript 0 end subscript over denominator 4 pi end fraction fraction numerator theta pi l over denominator d end fraction    

The correct answer is: 0


    By symmetry, the magnetic field at the centre P is zero.

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