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Physics-

General

Easy

Question

A string of length $L$ is fixed at one end and the string makes $fraction numerator 2 over denominator pi end fraction$ rev/s around the vertical axis through, the fixed and as shown in the figure, then tension in the string is

$M L$
$2 M L$
4 $M L$
16 $M L$

The correct answer is: 16 $blank M L$

$T sin invisible function application theta equals M omega to the power of 2 end exponent R$ (i)
$T sin invisible function application theta equals M omega to the power of 2 end exponent L blank s i n blank theta$ (ii)
$T equals M omega to the power of 2 end exponent L$
$equals M bullet 4 pi to the power of 2 end exponent n to the power of 2 end exponent L$
$equals M bullet 4 pi to the power of 2 end exponent open parentheses fraction numerator 2 over denominator pi end fraction close parentheses to the power of 2 end exponent L$
$equals 16 blank M L$

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