Physics-
General
Easy

Question

A system is taken through a cyclic process represented by a circle as shown. The heat absorbed by the system is

  1. pi cross times 1 0 to the power of 3 end exponent J    
  2. fraction numerator pi over denominator 2 end fraction J    
  3. 4 pi cross times 1 0 to the power of 2 end exponent J    
  4. pi J    

The correct answer is: fraction numerator pi over denominator 2 end fraction J


    In cyclic process DQ = Work done = Area inside the closed curve.
    Treat the circle as an ellipse of area equals fraction numerator pi over denominator 4 end fraction left parenthesis P subscript 2 end subscript minus P subscript 1 end subscript right parenthesis left parenthesis V subscript 2 end subscript minus V subscript 1 end subscript right parenthesis
    Þ capital delta Q equals fraction numerator pi over denominator 4 end fraction left curly bracket left parenthesis 150 minus 50 right parenthesis cross times 1 0 to the power of 3 end exponent right curly bracket equals fraction numerator pi over denominator 2 end fraction J

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