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General
Easy

Question

A transverse wave is passing through a light string shown in the figure The equation of wave is y equals A s i n invisible function application left parenthesis omega t minus k x right parenthesis The area of crosssection of string is A and density is ρ The hanging mass is

  1. Aomega    
  2. fraction numerator omega over denominator k g end fraction    
  3. fraction numerator rho A omega to the power of 2 end exponent over denominator k to the power of 2 end exponent g end fraction    
  4. fraction numerator k to the power of 2 end exponent g over denominator omega end fraction    

The correct answer is: fraction numerator rho A omega to the power of 2 end exponent over denominator k to the power of 2 end exponent g end fraction

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