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Physics-

General

Easy

Question

An ideal gas expands along the path AB as shown in the p-V diagram. The work done is

$4 \times 10^{4} J$
$1.2 \times 10^{5} J$
$2.4 \times 10^{5} J$
None of the above

The correct answer is: $1.2 cross times 10 to the power of 5 end exponent J$

Work done =area of trapezium
$equals fraction numerator 1 over denominator 2 end fraction cross times open parentheses 8 cross times 10 to the power of 5 end exponent plus 4 cross times 10 to the power of 5 end exponent close parentheses cross times 0.2$
$equals 1.2 cross times 10 to the power of 5 end exponent J$

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