Physics-
General
Easy

Question

An inductor open parentheses L equals 100 m H close parentheses comma a resistor open parentheses R equals 100 capital omega close parentheses and a battery open parentheses E equals 100 V close parentheses are initially connected in series as shown in the figure. After a long time the battery is disconnected after short circuiting the points A and B. The current in the circuit 1 ms after the short circuit is

  1. 1 A    
  2. 1 divided by e A    
  3. e A    
  4. 0.1 A    

The correct answer is: 1 divided by e A

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