Physics-
General
Easy

Question

An infinitely long conductor PQR is bent to form a right angle as shown. A current I flows through PQR The magnetic field due to this current at the point M is H1. Now another infinitely long straight conductor QS is connected at Q so that the current is I/2 in QR as well as in QS, The current in PQ remaining unchanged. The magnetic field at M is now H subscript 2. end subscriptThe ratio H subscript 1 end subscript divided by H subscript 2 end subscript is given by

  1. fraction numerator 1 over denominator 2 end fraction    
  2. 1    
  3. fraction numerator 2 over denominator 3 end fraction    
  4. 2    

The correct answer is: fraction numerator 2 over denominator 3 end fraction


    Magnetic field at any point lying on the current carrying straight conductor is zero.
    Here H1 = Magnetic field at M due to current in PQ.
    H2 = Magnetic field at M due to QR+ magnetic field at M due to QS+ magnetic field at M due to PQ
    equals 0 plus fraction numerator H subscript 1 end subscript over denominator 2 end fraction plus H subscript 1 end subscript equals fraction numerator 3 over denominator 2 end fraction H subscript 1 end subscript Þfraction numerator H subscript 1 end subscript over denominator H subscript 2 end subscript end fraction equals fraction numerator 2 over denominator 3 end fraction

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