Physics-
General
Easy
Question
Consider the circuit in the figure. The switch is initially in position A for a sufficiently long time to establish a steady state. At t = 0, the switch is turned to position B. The capacitor 2C did not hold any charge before t = 0.
The time, at which charge in the capacitor C is reduced to half of the value it had at t = 0, is
- 6RC ln2
- 3RC ln2
- 2RC ln2
- 4RC ln2
The correct answer is: 4RC ln2
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