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Physics-

General

Easy

Question

Consider the situation shown in figure. The horizontal surface below the bigger block is smooth. The coefficient of friction between the blocks is $mu.$ Find the minimum force F that can be applied in order to keep the smaller blocks at rest with respect to the bigger block.

$(M + 2 m) \frac{g (1 - μ)}{(1 + μ)}$
$(M + m) \frac{g (1 - μ)}{(1 + μ)}$
$(M + 2 m) \frac{g (1 + μ)}{(1 - μ)}$
$(M - 2 m) \frac{g (1 - μ)}{(1 + μ)}$

The correct answer is: $open parentheses M plus 2 m close parentheses fraction numerator g open parentheses 1 minus mu close parentheses over denominator open parentheses 1 plus mu close parentheses end fraction$

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