Current in the circuit will be

A 2V battery is connected across the points A and B as shown in the figure given below. Assuming that the resistance of each diode is zero in forward bias and infinity in reverse bias, the current supplied by the battery when its positive terminal is connected to A is

In the figure, ABC; is triangle in which C = 90º and AB = 5 cm. D is a point on AB such that AD = 3 cm and $angle A C D$ = 60º. Then the length of AC is –

the m-n theorem states that
(m + n) cot θ = m cot α – n cot ß
this gives us the cotangent of the angle CDA which is further used in the sine rule to find the length of AC

In the figure, ABC; is triangle in which C = 90º and AB = 5 cm. D is a point on AB such that AD = 3 cm and $angle A C D$ = 60º. Then the length of AC is –

the m-n theorem states that
(m + n) cot θ = m cot α – n cot ß
this gives us the cotangent of the angle CDA which is further used in the sine rule to find the length of AC

maths-

If f(x) = $fraction numerator 1 minus x over denominator 1 plus x end fraction$ , then $f left square bracket f left parenthesis sin invisible function application theta right parenthesis right square bracket$ equals

maths-General

The figure shows four wire loops, with edge lengths of either L or 2L. All four loops will move through a region of uniform magnetic field $stack B with rightwards arrow on top$ (directed out of the page) at the same constant velocity. Rank the four loops according to the maximum magnitude of the e.m.f. induced as they move through the field, greatest first

A magnet is made to oscillate with a particular frequency, passing through a coil as shown in figure. The time variation of the magnitude of e.m.f. generated across the coil during one cycle is

A square loop of side 5 cm enters a magnetic field with 1 cms^-1. The front edge enters the magnetic field at t = 0 then which graph best depicts emf

Switch S of the circuit shown in figure. is closed at t = 0. If e denotes the induced

emf in L and i, the current flowing through the circuit at time t, which of the following graphs is correct

The current i in an induction coil varies with time t according to the graph shown

in figure. Which of the following graphs shows the induced emf (e) in the coil with time

A flexible wire bent in the form of a circle is placed in a uniform magnetic field perpendicular to the plane of the coil. The radius of the coil changes as shown in figure. The graph of induced emf in the coil is represented by

When a certain circuit consisting of a constant e.m.f. E an inductance L and a resistance R is closed, the current in, it increases with time according to curve 1. After one parameter (E, L or R) is changed, the increase in current follows curve 2 when the circuit is closed second time. Which parameter was changed and in what direction

In the following figure, the magnet is moved towards the coil with a speed v and induced emf is e. If magnet and coil recede away from one another each moving with speed v, the induced emf in the coil will be

The equation $a x to the power of 2 end exponent plus b x plus c equals 0$ . where a, b, c are the sides of a ΔABC, and the equation $x to the power of 2 end exponent plus square root of 2 x plus 1 equals 0$ have a common root. The measure of $angle C$ is-

in a right angled isosceles triangle, ratio of sides = 1:√2:1
base angles are = 45 degrees.

The equation $a x to the power of 2 end exponent plus b x plus c equals 0$ . where a, b, c are the sides of a ΔABC, and the equation $x to the power of 2 end exponent plus square root of 2 x plus 1 equals 0$ have a common root. The measure of $angle C$ is-

in a right angled isosceles triangle, ratio of sides = 1:√2:1
base angles are = 45 degrees.

If in a ΔABC, (sin A + sin B + sin C)(sin A + sin B – sin C)= 3 sin A sin B, then –

the sine rule states that
a/sin A =b/sin B = c/sinC = 2R
this is used to find the relation of the angles and sides of the triangles.

If in a ΔABC, (sin A + sin B + sin C)(sin A + sin B – sin C)= 3 sin A sin B, then –

the sine rule states that
a/sin A =b/sin B = c/sinC = 2R
this is used to find the relation of the angles and sides of the triangles.

In the adjacent figure 'P' is any interior point of the equilateral triangle ABC of side length 2 unit –

If xa, xb and xc represent the distance of P from the sides BC, CA and AB respectively then xa + xb + xc is equal to -

area of equilateral triangle = √3a²/4
area of triangle = 1/2 x base x height

In the adjacent figure 'P' is any interior point of the equilateral triangle ABC of side length 2 unit –

If xa, xb and xc represent the distance of P from the sides BC, CA and AB respectively then xa + xb + xc is equal to -