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Physics-

General

Easy

Question

Four plates of equal area $A$ are separated by equal distance $d$ and are arranged as shown in the figure. The equivalent capacity is

$\frac{2 ε_{0} A}{d}$
$\frac{{3 ε}_{0} A}{d}$
$\frac{3 ε_{0} A}{2 d}$
$\frac{ε_{0} A}{d}$

The correct answer is: $fraction numerator 2 epsilon subscript 0 end subscript A over denominator d end fraction$

The given circuit is equivalent to a parallel combination of two identical capacitors.

Hence, equivalent capacitance between points $A a n d blank B$ is
$C equals fraction numerator epsilon subscript 0 end subscript A over denominator d end fraction plus fraction numerator epsilon subscript 0 end subscript A over denominator d end fraction equals fraction numerator 2 epsilon subscript 0 end subscript A over denominator d end fraction$

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