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Physics-

General

Easy

Question

From a solid sphere of mass M and radius R, a spherical portion of radius R/2 is removed, as shown in the figure. Taking gravitational potential V = 0 at r = $infinity$ , the potential at the centre of the cavityh thus formed is : (G = gravitational constant)

$\frac{- 2 G M}{3 R}$
$\frac{- 2 G M}{R}$
$\frac{- G M}{2 R}$
$\frac{- G M}{R}$

The correct answer is: $fraction numerator negative G M over denominator R end fraction$

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