Physics-
General
Easy

Question

In an L–R series circuit, a sinusoidal voltage V equals V subscript 0 end subscript s i n invisible function application omega t is applied. It is given that L = 35 mH, R = 11capital omega, Vrms = 220 V, omega divided by 2 pi equals 50 H z and pi = 22/7. Find the amplitude of current in the steady state and obtain the phase difference between the current and the voltage. Also plot the variation of current for one cycle on the given graph.

An AC voltage source of variable angular frequency omega and fixed amplitude V connected in series with a capacitance C and an electric bulb of resistance R (inductance zero). When omega is increased :

  1. the bulb glows dimmer    
  2. the bulb glows brighter    
  3. total impedence of the circuit is unchanged    
  4. total impedence of the circuit increases    

The correct answer is: the bulb glows brighter


    I subscript r m s end subscript equals fraction numerator V subscript r m s end subscript over denominator square root of R to the power of 2 end exponent plus fraction numerator 1 over denominator omega to the power of 2 end exponent c to the power of 2 end exponent end fraction end root end fraction
    when omega increases, irms increases so the bulb glows brighter

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