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Physics-

General

Easy

Question

In the AC circuit shown below, the supply voltage has constant rms value V but variable frequency f. At resonance, the circuit :

has a current I given by $I = \frac{V}{R}$
has a resonance frequency 500 Hz
has a voltage across the capacitor which is $180^{\circ}$ out of phase with that across the inductor
has a current given by I= $\frac{V}{\sqrt{R^{2} + {(\frac{1}{π} + \frac{1}{π})}^{2}}}$

The correct answer is: has a resonance frequency 500 Hz

Resonance frequency $f equals fraction numerator 1 over denominator 2 pi end fraction fraction numerator 1 over denominator square root of L C end root end fraction equals 500 H z$
At resonance
$table row cell Z equals R end cell row cell text end text text. end text text end text I equals fraction numerator V over denominator z end fraction equals fraction numerator V over denominator R end fraction end cell end table$

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