Physics-
General
Easy

Question

In the circuit diagram shown

  1. time constant is L/R    
  2. time constant is 2L/R    
  3. steady state current in inductor is 2 epsilon divided by R    
  4. steady state current in inductor is epsilon divided by R    

The correct answer is: time constant is L/R


    Since the other resistance is attached parallel to the battery hence the time constant of the circuit will be L/R . At steady State the inductor offers zero resistance have hence at that time current in inductor will be E/R .

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