Physics-
General
Easy
Question
One ice skater of mass m moves with speed 2v to the right, while another of the same mass m moves with speed v toward the left, as shown in figure I. Their paths are separated by a distance b. At t = 0, when they are both at x = 0, they grasp a pole of length b and negligible mass. For t > 0, consider the system as a rigid body of two masses m separated by distance b, as shown in figure II. Which of the following is the correct formula for the motion after t = 0 of the skater initially at y = b/2?
- x = 2vt, y = b / 2
- x = vt + 0.5b sin (3vt / b), y = 0.5b cos (3vt / b)
- x = 0.5vt + 0.5b sin (3vt / b), y = 0.5b cos (3vt / b)
- x = 0.5vt + 0.5b sin (6vt / b), y = 0.5b cos (6vt / b)
The correct answer is: x = 2vt, y = b / 2
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