Physics-
General
Easy

Question

The following diagram indicates the energy levels of a certain atom when the system moves from 4 E level to E. A photon of wavelength lambda subscript 1 end subscript is emitted. The wavelength of photon produced during it’s transition from fraction numerator 7 over denominator 3 end fraction E level to Eis lambda subscript 2 end subscript. The ratio fraction numerator lambda subscript 1 end subscript over denominator lambda subscript 2 end subscript end fraction will be

  1. fraction numerator 9 over denominator 4 end fraction    
  2. fraction numerator 4 over denominator 9 end fraction    
  3. fraction numerator 3 over denominator 2 end fraction    
  4. fraction numerator 7 over denominator 3 end fraction    

The correct answer is: fraction numerator 4 over denominator 9 end fraction


    Transition from 4 E to E
    open parentheses 4 E minus E close parentheses equals fraction numerator h c over denominator lambda subscript 1 end subscript end fraction rightwards double arrow lambda subscript 1 end subscript equals fraction numerator h c over denominator 3 E end fraction(i)
    Transition from fraction numerator 7 over denominator 3 end fraction E to E
    open parentheses fraction numerator 7 over denominator 3 end fraction E minus E close parentheses equals fraction numerator h c over denominator lambda subscript 2 end subscript end fraction rightwards double arrow lambda subscript 2 end subscript equals fraction numerator 3 h c over denominator 4 E end fraction(ii)
    From equation (i) and (ii), fraction numerator lambda subscript 1 end subscript over denominator lambda subscript 2 end subscript end fraction equals fraction numerator 4 over denominator 9 end fraction

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