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Physics-

General

Easy

Question

The magnetic induction at O due to a current in conductor shaped as shown in fig is

$\frac{μ_{o} i}{4 π} [\frac{3 π}{2 a} + \frac{\sqrt{2}}{b}]$
$\frac{μ_{o} i}{4 π} [\frac{3 π}{4 a} - \frac{\sqrt{2}}{b}]$
$\frac{μ_{o} i}{2 π} [\frac{3 π}{4 a} + \frac{1}{\sqrt{2} b}]$
$\frac{μ_{o} i}{4 π} [\frac{1}{a} + \frac{1}{b}]$

The correct answer is: $fraction numerator mu subscript o end subscript i over denominator 4 pi end fraction open square brackets fraction numerator 3 pi over denominator 2 a end fraction plus fraction numerator square root of 2 over denominator b end fraction close square brackets$

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