Physics-
General
Easy

Question

The resistance of a germanium junction diode whose V minus I is shown in figure is left parenthesis V subscript k end subscript equals 0.3 V right parenthesis

  1. 5 k capital omega    
  2. 0.2 k capital omega    
  3. 2.3 k capital omega    
  4. open parentheses fraction numerator 10 over denominator 2.3 end fraction close parentheses k capital omega    

The correct answer is: 0.2 k capital omega


    V subscript k end subscript= knee voltage = 0.3 V
    thereforeResistance equals fraction numerator capital delta V over denominator capital delta i end fraction equals fraction numerator left parenthesis 2.3 minus 0.3 right parenthesis over denominator left parenthesis 10 minus 0 right parenthesis cross times 1 0 to the power of negative 3 end exponent end fraction equals 200 capital omega equals 0.2 k capital omega

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