Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Physics-

General

Easy

Question

The variation of velocity of a particle with time moving along a straight line is illustrated in the following figure. The distance travelled by the particle in four seconds is :

60 m
55 m
25 m
30 m

The correct answer is: 55 m

Related Questions to study

A particle is dropped vertically from rest from a height. The time taken by it to fall through successive distance of 1 m each will then be :

A particle is dropped vertically from rest from a height. The time taken by it to fall through successive distance of 1 m each will then be :

Physics-General

A particle starts from rest. Its acceleration (A) versus time (t) is as shown in the figure. The maximum speed of the particle will be :

A particle starts from rest. Its acceleration (A) versus time (t) is as shown in the figure. The maximum speed of the particle will be :

physics-General

A boat is moving with velocity of $3 stack i with hat on top plus 4 stack j with hat on top$ in river and water is moving with a velocity of $negative 3 stack i with hat on top minus 4 stack j with hat on top$ with respect to ground. Relative velocity of boat with respect to water is :

A boat is moving with velocity of $3 stack i with hat on top plus 4 stack j with hat on top$ in river and water is moving with a velocity of $negative 3 stack i with hat on top minus 4 stack j with hat on top$ with respect to ground. Relative velocity of boat with respect to water is :

Physics-General

parallel

A man is 45 m behind the bus when the bus start accelerating from rest with acceleration 2.5 m/s² With what minimum velocity should the man start running to catch the bus?

A man is 45 m behind the bus when the bus start accelerating from rest with acceleration 2.5 m/s² With what minimum velocity should the man start running to catch the bus?

Physics-General

The position of a particle moving along the x-axis at certain times is given below :

Which of the following describes the motion correctly :

The position of a particle moving along the x-axis at certain times is given below :

Which of the following describes the motion correctly :

physics-General

For a moving body at any instant of time :

For a moving body at any instant of time :

Physics-General

parallel

The velocity of a body depends on time according to the equation u = 20 + 0.1t² The body is undergoing:

The velocity of a body depends on time according to the equation u = 20 + 0.1t² The body is undergoing:

Physics-General

If $integral s e c to the power of fraction numerator 4 over denominator 9 end fraction end exponent invisible function application x times c o s invisible function application e to the power of fraction numerator 14 over denominator 9 end fraction end exponent x d x equals a t a n to the power of b end exponent invisible function application x plus c$ then a+b= ___

If $integral s e c to the power of fraction numerator 4 over denominator 9 end fraction end exponent invisible function application x times c o s invisible function application e to the power of fraction numerator 14 over denominator 9 end fraction end exponent x d x equals a t a n to the power of b end exponent invisible function application x plus c$ then a+b= ___

The value of constant a>0 such that $stretchy integral subscript 0 end subscript superscript a end superscript open square brackets tan to the power of negative 1 end exponent invisible function application square root of x close square brackets d x equals stretchy integral subscript 0 end subscript superscript a end superscript open square brackets cot to the power of negative 1 end exponent invisible function application square root of x close square brackets d x$ where [.] denotes G.I.F is

The value of constant a>0 such that $stretchy integral subscript 0 end subscript superscript a end superscript open square brackets tan to the power of negative 1 end exponent invisible function application square root of x close square brackets d x equals stretchy integral subscript 0 end subscript superscript a end superscript open square brackets cot to the power of negative 1 end exponent invisible function application square root of x close square brackets d x$ where [.] denotes G.I.F is

parallel

Let $text end text f colon R to the power of plus end exponent rightwards arrow R$ be a differentiable function with $f left parenthesis A right parenthesis equals 3$ and satisfying $stretchy integral subscript 1 end subscript superscript x y end superscript f left parenthesis t right parenthesis d t equals y stretchy integral subscript 1 end subscript superscript x end superscript f left parenthesis t right parenthesis d t plus x stretchy integral subscript 1 end subscript superscript y end superscript f left parenthesis t right parenthesis d t for all x comma y element of R to the power of plus end exponent comma text then end text f left parenthesis x right parenthesis equals$

Let $text end text f colon R to the power of plus end exponent rightwards arrow R$ be a differentiable function with $f left parenthesis A right parenthesis equals 3$ and satisfying $stretchy integral subscript 1 end subscript superscript x y end superscript f left parenthesis t right parenthesis d t equals y stretchy integral subscript 1 end subscript superscript x end superscript f left parenthesis t right parenthesis d t plus x stretchy integral subscript 1 end subscript superscript y end superscript f left parenthesis t right parenthesis d t for all x comma y element of R to the power of plus end exponent comma text then end text f left parenthesis x right parenthesis equals$

Area bounded by the curve $y to the power of 2 end exponent equals x plus 4$ and the line x+2y=4 is _____ sq. units

Area bounded by the curve $y to the power of 2 end exponent equals x plus 4$ and the line x+2y=4 is _____ sq. units

Area of the figure contained between the parabola $x to the power of 2 end exponent equals 4 y$ and the curve $y equals fraction numerator 8 over denominator x to the power of 2 end exponent plus 4 end fraction text is end text 2 pi minus K$ then K=

Area of the figure contained between the parabola $x to the power of 2 end exponent equals 4 y$ and the curve $y equals fraction numerator 8 over denominator x to the power of 2 end exponent plus 4 end fraction text is end text 2 pi minus K$ then K=

parallel

The area bounded by mini $left parenthesis vertical line x vertical line comma vertical line y vertical line right parenthesis equals 2 text end text$ and $m a x left parenthesis vertical line x vertical line comma vertical line y vertical line right parenthesis equals 4 text is : end text$

The area bounded by mini $left parenthesis vertical line x vertical line comma vertical line y vertical line right parenthesis equals 2 text end text$ and $m a x left parenthesis vertical line x vertical line comma vertical line y vertical line right parenthesis equals 4 text is : end text$

$f left parenthesis x right parenthesis equals stretchy integral subscript 1 end subscript superscript x end superscript fraction numerator tan to the power of negative 1 end exponent invisible function application t over denominator t end fraction d t semicolon x greater than 0$ then the value of $f open parentheses e to the power of 2 end exponent close parentheses minus f open parentheses fraction numerator 1 over denominator e to the power of 2 end exponent end fraction close parentheses text is end text$

$f left parenthesis x right parenthesis equals stretchy integral subscript 1 end subscript superscript x end superscript fraction numerator tan to the power of negative 1 end exponent invisible function application t over denominator t end fraction d t semicolon x greater than 0$ then the value of $f open parentheses e to the power of 2 end exponent close parentheses minus f open parentheses fraction numerator 1 over denominator e to the power of 2 end exponent end fraction close parentheses text is end text$

$integral left parenthesis square root of c o t invisible function application x end root plus square root of t a n invisible function application x end root right parenthesis d x equals f left parenthesis x right parenthesis plus c text thenf end text left parenthesis x right parenthesis equals$

$integral left parenthesis square root of c o t invisible function application x end root plus square root of t a n invisible function application x end root right parenthesis d x equals f left parenthesis x right parenthesis plus c text thenf end text left parenthesis x right parenthesis equals$

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.