Physics-
General
Easy

Question

The velocity-time graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in 6 sec are respectively

  1. 8 m, 16 m    
  2. 16 m, 8 m    
  3. 16 m, 16 m    
  4. 8 m, 8 m    

The correct answer is: 8 m, 16 m


    Displacement = Summation of all the area with sign
    equals open parentheses A subscript 1 end subscript close parentheses plus open parentheses negative A subscript 2 end subscript close parentheses plus open parentheses A subscript 3 end subscript close parentheses
    equals left parenthesis 2 cross times 4 right parenthesis plus left parenthesis negative 2 cross times 2 right parenthesis plus left parenthesis 2 cross times 2 right parenthesis

    therefore Displacement = 8 m
    Distance =Summation of all the areas without sign
    equals vertical line A subscript 1 end subscript vertical line plus vertical line minus A subscript 2 end subscript vertical line plus vertical line A subscript 3 end subscript vertical line   equals vertical line 8 vertical line plus vertical line minus 4 vertical line plus vertical line 4 vertical line=8 plus 4 plus 4
    therefore Distance = 16 m.

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