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Physics-

General

Easy

Question

There are two blocks A and B is contact with vertical and horizontal smooth surface respectively. Acceleration of A and B are a_A and a_B respectively along their constrained direction of motions. Relation between a_A and a_B is (Assume $sin invisible function application blank 23 degree equals fraction numerator 2 over denominator 5 end fraction$ ).

$2 a_{A} = \sqrt{21} a_{B}$
2a_A = 5a_B
5a_A = 2a_B
$\sqrt{21}$ a_A = 2a_B.

The correct answer is: $square root of 21$ a_A = 2a_B.

Perpendicular to surface their acceleration components must be equal.
A_A cos q = a_B sin q
$square root of 21$ a_A = 2a_B.sin q = $fraction numerator 2 over denominator 5 end fraction$

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