Three equal masses A, B and C are pulled with a constant force F. They are connected to each other with strings. The ratio of the tension between AB and BC is.

The forces exerted by A on B, B on C, C on D and D on ground are.

Three masses of 16kg, 8kg, and 4kg are placed in contact as shown in figure. If a force of 140N is applied on 16kg mass the force acting on 8kg mass is.

Three blocks are connected as shown in the figure on a horizontal friction less table. If $M_1=1kg,M_2=8kg,M_3=27kg\text{ and }{T}_3=36N\text{ , }$then T₂ will be.

Two blocks of masses 2kg and 1kg are in contact with each other on a friction less table. When a horizontal force of 3N is applied on the block of mass 2kg, the value of the force of contact between the two blocks is.

Two masses m₁ and m₂ are placed on a smooth surface horizontally and connected by a light string as shown in figure A force F is applied on mass m₁, then the tension in the string T₂ is.

Two masses m₁ and m₂ are suspended from a rigid support through a light string. The tension in the string between support and mass m₁ is.

If the angle of friction is 45, then the coefficient of static friction is.

A block of mass 2kg lies on a horizontal surface and it is subjected to a vertical downward force 30N as shown in figure. The contact force between the block and surface is.

The free body diagram of block 'm' is

If and , then all the values of lie on

Therefore the correct option is choice 4

If is a complex number such that then the minimum value of is is strictly

Therefore the correct option is choice 4

If and then

Therefore the correct option is choice 3

One of the values of

If the distance between the points , is
then 6
Assertion (A): If , then lies between

Reason If , then

If then a+b+c=

So here we have used the trigonometric functions and trigonometric formulas to solve this, the algebraic expressions were used to formulate it. Here the answer of a+b+c is 7.