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Physics-

General

Easy

Question

Three long, straight parallel wires, carrying current, are arranged as shown in figure. The force experienced by a 25 cm length of wire $C$ is

$10^{- 3} N$
$2.5 \times 10^{- 3} N$
Zero
$1.5 \times 10^{- 3}$

The correct answer is: Zero

Force on wire $C$ due to wire $D.$
$F subscript 1 end subscript equals fraction numerator mu subscript 0 end subscript over denominator 2 pi end fraction fraction numerator I subscript 1 end subscript I subscript 2 end subscript over denominator r end fraction l$ (repulsive)
$blank equals 2 cross times 10 to the power of negative 7 end exponent cross times fraction numerator 30 cross times 10 over denominator 3 cross times 10 to the power of negative 2 end exponent end fraction cross times 25 cross times 10 to the power of negative 2 end exponent$
$blank equals 2 cross times 10 to the power of negative 7 end exponent cross times 2500 equals 5 cross times 10 to the power of negative 4 end exponent N$
Force on wire $C$ due to wire $G$
$F subscript 2 end subscript equals fraction numerator mu subscript 0 end subscript over denominator 2 pi end fraction fraction numerator I subscript 1 end subscript I subscript 2 end subscript over denominator r end fraction l$ (repulsive)
$blank equals fraction numerator 2 cross times 10 to the power of negative 7 end exponent cross times 10 cross times 20 over denominator 2 cross times 10 to the power of negative 2 end exponent end fraction cross times 25 cross times 10 to the power of negative 2 end exponent$
$blank equals 2 cross times 10 to the power of negative 7 end exponent cross times 2500 equals 5 cross times 10 to the power of negative 4 end exponent N$
Net force $equals F subscript 1 end subscript minus F subscript 2 end subscript equals 5 cross times 10 to the power of negative 4 end exponent N minus 5 cross times 10 to the power of negative 4 end exponent N equals 0$

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